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(5x+35)=(2x+20)
We move all terms to the left:
(5x+35)-((2x+20))=0
We get rid of parentheses
5x-((2x+20))+35=0
We calculate terms in parentheses: -((2x+20)), so:We get rid of parentheses
(2x+20)
We get rid of parentheses
2x+20
Back to the equation:
-(2x+20)
5x-2x-20+35=0
We add all the numbers together, and all the variables
3x+15=0
We move all terms containing x to the left, all other terms to the right
3x=-15
x=-15/3
x=-5
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