-3(v+2)=5v-9+5(2v+3)

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Solution for -3(v+2)=5v-9+5(2v+3) equation: 



-3(v+2)=5v-9+5(2v+3)

We move all terms to the left:

-3(v+2)-(5v-9+5(2v+3))=0

We multiply parentheses

-3v-(5v-9+5(2v+3))-6=0



We calculate terms in parentheses: -(5v-9+5(2v+3)), so:

5v-9+5(2v+3)

determiningTheFunctionDomain
5v+5(2v+3)-9

We multiply parentheses

5v+10v+15-9

We add all the numbers together, and all the variables

15v+6

Back to the equation:

-(15v+6)



We get rid of parentheses

-3v-15v-6-6=0

We add all the numbers together, and all the variables

-18v-12=0

We move all terms containing v to the left, all other terms to the right

-18v=12

v=12/-18

v=-2/3

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