9+2(7v-6)=-5(2v-1)+8v

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Solution for 9+2(7v-6)=-5(2v-1)+8v equation: 



9+2(7v-6)=-5(2v-1)+8v

We move all terms to the left:

9+2(7v-6)-(-5(2v-1)+8v)=0

We multiply parentheses

14v-(-5(2v-1)+8v)-12+9=0



We calculate terms in parentheses: -(-5(2v-1)+8v), so:

-5(2v-1)+8v

We add all the numbers together, and all the variables

8v-5(2v-1)

We multiply parentheses

8v-10v+5

We add all the numbers together, and all the variables

-2v+5

Back to the equation:

-(-2v+5)



We add all the numbers together, and all the variables

14v-(-2v+5)-3=0

We get rid of parentheses

14v+2v-5-3=0

We add all the numbers together, and all the variables

16v-8=0

We move all terms containing v to the left, all other terms to the right

16v=8

v=8/16

v=1/2

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