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-3(v+1)=5v-8+2(5v+1)
We move all terms to the left:
-3(v+1)-(5v-8+2(5v+1))=0
We multiply parentheses
-3v-(5v-8+2(5v+1))-3=0
We calculate terms in parentheses: -(5v-8+2(5v+1)), so:We get rid of parentheses
5v-8+2(5v+1)
determiningTheFunctionDomain 5v+2(5v+1)-8
We multiply parentheses
5v+10v+2-8
We add all the numbers together, and all the variables
15v-6
Back to the equation:
-(15v-6)
-3v-15v+6-3=0
We add all the numbers together, and all the variables
-18v+3=0
We move all terms containing v to the left, all other terms to the right
-18v=-3
v=-3/-18
v=1/6
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