-3(4v-6)+8v=2(v+4)

Solution for -3(4v-6)+8v=2(v+4) equation:

-3(4v-6)+8v=2(v+4)

We move all terms to the left:

-3(4v-6)+8v-(2(v+4))=0

We add all the numbers together, and all the variables

8v-3(4v-6)-(2(v+4))=0

We multiply parentheses

8v-12v-(2(v+4))+18=0


We calculate terms in parentheses: -(2(v+4)), so:

2(v+4)

We multiply parentheses

2v+8

Back to the equation:

-(2v+8)


We add all the numbers together, and all the variables

-4v-(2v+8)+18=0

We get rid of parentheses

-4v-2v-8+18=0

We add all the numbers together, and all the variables

-6v+10=0

We move all terms containing v to the left, all other terms to the right

-6v=-10

v=-10/-6

v=1+2/3