-3(u+1)=u-7+2(7u+7)

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Solution for -3(u+1)=u-7+2(7u+7) equation: 



-3(u+1)=u-7+2(7u+7)

We move all terms to the left:

-3(u+1)-(u-7+2(7u+7))=0

We multiply parentheses

-3u-(u-7+2(7u+7))-3=0



We calculate terms in parentheses: -(u-7+2(7u+7)), so:

u-7+2(7u+7)

determiningTheFunctionDomain
u+2(7u+7)-7

We multiply parentheses

u+14u+14-7

We add all the numbers together, and all the variables

15u+7

Back to the equation:

-(15u+7)



We get rid of parentheses

-3u-15u-7-3=0

We add all the numbers together, and all the variables

-18u-10=0

We move all terms containing u to the left, all other terms to the right

-18u=10

u=10/-18

u=-5/9

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