-3(s-20)=12

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Solution for -3(s-20)=12 equation: 



-3(s-20)=12

We move all terms to the left:

-3(s-20)-(12)=0

We multiply parentheses

-3s+60-12=0

We add all the numbers together, and all the variables

-3s+48=0

We move all terms containing s to the left, all other terms to the right

-3s=-48

s=-48/-3

s=+16

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