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1/2(x+4)=1/2(x-8)
We move all terms to the left:
1/2(x+4)-(1/2(x-8))=0
Domain of the equation: 2(x+4)!=0
x∈R
Domain of the equation: 2(x-8))!=0We calculate fractions
x∈R
(2xx/(2(x+4)*2(x-8)))+(-2xx/(2(x+4)*2(x-8)))=0
We calculate terms in parentheses: +(2xx/(2(x+4)*2(x-8))), so:
2xx/(2(x+4)*2(x-8))
We multiply all the terms by the denominator
2xx
Back to the equation:
+(2xx)
We calculate terms in parentheses: +(-2xx/(2(x+4)*2(x-8))), so:We get rid of parentheses
-2xx/(2(x+4)*2(x-8))
We multiply all the terms by the denominator
-2xx
Back to the equation:
+(-2xx)
2xx-2xx=0
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