-3(m-4)=2(-3m+11)

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Solution for -3(m-4)=2(-3m+11) equation: 



-3(m-4)=2(-3m+11)

We move all terms to the left:

-3(m-4)-(2(-3m+11))=0

We multiply parentheses

-3m-(2(-3m+11))+12=0



We calculate terms in parentheses: -(2(-3m+11)), so:

2(-3m+11)

We multiply parentheses

-6m+22

Back to the equation:

-(-6m+22)



We get rid of parentheses

-3m+6m-22+12=0

We add all the numbers together, and all the variables

3m-10=0

We move all terms containing m to the left, all other terms to the right

3m=10

m=10/3

m=3+1/3

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