3(y+1)=40-2y

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Solution for 3(y+1)=40-2y equation: 



3(y+1)=40-2y

We move all terms to the left:

3(y+1)-(40-2y)=0

We add all the numbers together, and all the variables

3(y+1)-(-2y+40)=0

We multiply parentheses

3y-(-2y+40)+3=0

We get rid of parentheses

3y+2y-40+3=0

We add all the numbers together, and all the variables

5y-37=0

We move all terms containing y to the left, all other terms to the right

5y=37

y=37/5

y=7+2/5

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