-3(c-4)-2c-8=9(c+2)+1=

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Solution for -3(c-4)-2c-8=9(c+2)+1= equation: 



-3(c-4)-2c-8=9(c+2)+1=

We move all terms to the left:

-3(c-4)-2c-8-(9(c+2)+1)=0

We add all the numbers together, and all the variables

-2c-3(c-4)-(9(c+2)+1)-8=0

We multiply parentheses

-2c-3c-(9(c+2)+1)+12-8=0



We calculate terms in parentheses: -(9(c+2)+1), so:

9(c+2)+1

We multiply parentheses

9c+18+1

We add all the numbers together, and all the variables

9c+19

Back to the equation:

-(9c+19)



We add all the numbers together, and all the variables

-5c-(9c+19)+4=0

We get rid of parentheses

-5c-9c-19+4=0

We add all the numbers together, and all the variables

-14c-15=0

We move all terms containing c to the left, all other terms to the right

-14c=15

c=15/-14

c=-1+1/14

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