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1/2(12z+10)-4=5(z-3)
We move all terms to the left:
1/2(12z+10)-4-(5(z-3))=0
Domain of the equation: 2(12z+10)!=0We multiply all the terms by the denominator
z∈R
-((5(z-3)))*2(12z+10)-4*2(12z+10)+1=0
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:Wy multiply elements
(5(z-3)))*2(12z+10
-((5(z-3)))*2(12z+10)-8z(1+1=0
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
We calculate terms in parentheses: -((5(z-3)))*2(12z+10), so:
(5(z-3)))*2(12z+10
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