-3(c-4)-2-8=9(c+2)+1

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Solution for -3(c-4)-2-8=9(c+2)+1 equation: 



-3(c-4)-2-8=9(c+2)+1

We move all terms to the left:

-3(c-4)-2-8-(9(c+2)+1)=0

We add all the numbers together, and all the variables

-3(c-4)-(9(c+2)+1)-10=0

We multiply parentheses

-3c-(9(c+2)+1)+12-10=0



We calculate terms in parentheses: -(9(c+2)+1), so:

9(c+2)+1

We multiply parentheses

9c+18+1

We add all the numbers together, and all the variables

9c+19

Back to the equation:

-(9c+19)



We add all the numbers together, and all the variables

-3c-(9c+19)+2=0

We get rid of parentheses

-3c-9c-19+2=0

We add all the numbers together, and all the variables

-12c-17=0

We move all terms containing c to the left, all other terms to the right

-12c=17

c=17/-12

c=-1+5/12

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