8(3x-x)=(9x-4)3

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Solution for 8(3x-x)=(9x-4)3 equation: 



8(3x-x)=(9x-4)3

We move all terms to the left:

8(3x-x)-((9x-4)3)=0

We add all the numbers together, and all the variables

8(+2x)-((9x-4)3)=0

We multiply parentheses

16x-((9x-4)3)=0



We calculate terms in parentheses: -((9x-4)3), so:

(9x-4)3

We multiply parentheses

27x-12

Back to the equation:

-(27x-12)



We get rid of parentheses

16x-27x+12=0

We add all the numbers together, and all the variables

-11x+12=0

We move all terms containing x to the left, all other terms to the right

-11x=-12

x=-12/-11

x=1+1/11

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