-3(c-3)=3(3+2c)

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Solution for -3(c-3)=3(3+2c) equation: 



-3(c-3)=3(3+2c)

We move all terms to the left:

-3(c-3)-(3(3+2c))=0

We add all the numbers together, and all the variables

-3(c-3)-(3(2c+3))=0

We multiply parentheses

-3c-(3(2c+3))+9=0



We calculate terms in parentheses: -(3(2c+3)), so:

3(2c+3)

We multiply parentheses

6c+9

Back to the equation:

-(6c+9)



We get rid of parentheses

-3c-6c-9+9=0

We add all the numbers together, and all the variables

-9c=0

c=0/-9

c=0

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