6(2x2+2)=20

Solution for 6(2x2+2)=20 equation:

6(2x^2+2)=20

We move all terms to the left:

6(2x^2+2)-(20)=0

We multiply parentheses

12x^2+12-20=0

We add all the numbers together, and all the variables

12x^2-8=0

a = 12; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·12·(-8)
Δ = 384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{384}=\sqrt{64*6}=\sqrt{64}*\sqrt{6}=8\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{6}}{2*12}=\frac{0-8\sqrt{6}}{24}
=-\frac{8\sqrt{6}}{24}
=-\frac{\sqrt{6}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{6}}{2*12}=\frac{0+8\sqrt{6}}{24}
=\frac{8\sqrt{6}}{24}
=\frac{\sqrt{6}}{3}
$