-3(b-6)=7(-3b-2)-4

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Solution for -3(b-6)=7(-3b-2)-4 equation: 



-3(b-6)=7(-3b-2)-4

We move all terms to the left:

-3(b-6)-(7(-3b-2)-4)=0

We multiply parentheses

-3b-(7(-3b-2)-4)+18=0



We calculate terms in parentheses: -(7(-3b-2)-4), so:

7(-3b-2)-4

We multiply parentheses

-21b-14-4

We add all the numbers together, and all the variables

-21b-18

Back to the equation:

-(-21b-18)



We get rid of parentheses

-3b+21b+18+18=0

We add all the numbers together, and all the variables

18b+36=0

We move all terms containing b to the left, all other terms to the right

18b=-36

b=-36/18

b=-2

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