(2x+16)+(3x-6)+(5x-50)=180

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Solution for (2x+16)+(3x-6)+(5x-50)=180 equation:



(2x+16)+(3x-6)+(5x-50)=180
We move all terms to the left:
(2x+16)+(3x-6)+(5x-50)-(180)=0
We get rid of parentheses
2x+3x+5x+16-6-50-180=0
We add all the numbers together, and all the variables
10x-220=0
We move all terms containing x to the left, all other terms to the right
10x=220
x=220/10
x=22

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