-3(a+7a-3)=(-26-a)-11

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Solution for -3(a+7a-3)=(-26-a)-11 equation: 



-3(a+7a-3)=(-26-a)-11

We move all terms to the left:

-3(a+7a-3)-((-26-a)-11)=0

We add all the numbers together, and all the variables

-3(8a-3)-((-1a-26)-11)=0

We multiply parentheses

-24a-((-1a-26)-11)+9=0



We calculate terms in parentheses: -((-1a-26)-11), so:

(-1a-26)-11

We get rid of parentheses

-1a-26-11

We add all the numbers together, and all the variables

-1a-37

Back to the equation:

-(-1a-37)



We get rid of parentheses

-24a+1a+37+9=0

We add all the numbers together, and all the variables

-23a+46=0

We move all terms containing a to the left, all other terms to the right

-23a=-46

a=-46/-23

a=+2

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