(2/3)m+2=(1/6)m-3

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Solution for (2/3)m+2=(1/6)m-3 equation: 



(2/3)m+2=(1/6)m-3

We move all terms to the left:

(2/3)m+2-((1/6)m-3)=0



Domain of the equation: 3)m!=0

m!=0/1

m!=0

m∈R





Domain of the equation: 6)m-3)!=0

m!=0/1

m!=0

m∈R



We add all the numbers together, and all the variables

(+2/3)m-((+1/6)m-3)+2=0

We multiply parentheses

2m^2-((+1/6)m-3)+2=0

We multiply all the terms by the denominator


2m^2*6)m-3)-((+2*6)m-3)+1=0

We add all the numbers together, and all the variables

2m^2*6)m-3)-(12m-3)+1=0

Wy multiply elements

12m^3=0

We do not support empression: m^3

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