(2/3m)+2=(1/6m)-3

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Solution for (2/3m)+2=(1/6m)-3 equation: 



(2/3m)+2=(1/6m)-3

We move all terms to the left:

(2/3m)+2-((1/6m)-3)=0



Domain of the equation: 3m)!=0

m!=0/1

m!=0

m∈R





Domain of the equation: 6m)-3)!=0

m!=0/1

m!=0

m∈R



We add all the numbers together, and all the variables

(+2/3m)-((+1/6m)-3)+2=0

We get rid of parentheses

2/3m-((+1/6m)-3)+2=0

We calculate fractions


12m/18m^2+(-((+1*3m)/18m^2+2=0

We calculate fractions

We do not support empression: m^4

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