-3(7y-2)+7y=2(y+5)

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Solution for -3(7y-2)+7y=2(y+5) equation: 



-3(7y-2)+7y=2(y+5)

We move all terms to the left:

-3(7y-2)+7y-(2(y+5))=0

We add all the numbers together, and all the variables

7y-3(7y-2)-(2(y+5))=0

We multiply parentheses

7y-21y-(2(y+5))+6=0



We calculate terms in parentheses: -(2(y+5)), so:

2(y+5)

We multiply parentheses

2y+10

Back to the equation:

-(2y+10)



We add all the numbers together, and all the variables

-14y-(2y+10)+6=0

We get rid of parentheses

-14y-2y-10+6=0

We add all the numbers together, and all the variables

-16y-4=0

We move all terms containing y to the left, all other terms to the right

-16y=4

y=4/-16

y=-1/4

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