-6(2u-2)+4u=6+2(4u-4)

Solution for -6(2u-2)+4u=6+2(4u-4) equation:

-6(2u-2)+4u=6+2(4u-4)

We move all terms to the left:

-6(2u-2)+4u-(6+2(4u-4))=0

We add all the numbers together, and all the variables

4u-6(2u-2)-(6+2(4u-4))=0

We multiply parentheses

4u-12u-(6+2(4u-4))+12=0


We calculate terms in parentheses: -(6+2(4u-4)), so:

6+2(4u-4)

determiningTheFunctionDomain
2(4u-4)+6

We multiply parentheses

8u-8+6

We add all the numbers together, and all the variables

8u-2

Back to the equation:

-(8u-2)


We add all the numbers together, and all the variables

-8u-(8u-2)+12=0

We get rid of parentheses

-8u-8u+2+12=0

We add all the numbers together, and all the variables

-16u+14=0

We move all terms containing u to the left, all other terms to the right

-16u=-14

u=-14/-16

u=7/8