-3(6j+5)+12j=7

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Solution for -3(6j+5)+12j=7 equation: 



-3(6j+5)+12j=7

We move all terms to the left:

-3(6j+5)+12j-(7)=0

We add all the numbers together, and all the variables

12j-3(6j+5)-7=0

We multiply parentheses

12j-18j-15-7=0

We add all the numbers together, and all the variables

-6j-22=0

We move all terms containing j to the left, all other terms to the right

-6j=22

j=22/-6

j=-3+2/3

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