3(n-2)+4n=64

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Solution for 3(n-2)+4n=64 equation: 



3(n-2)+4n=64

We move all terms to the left:

3(n-2)+4n-(64)=0

We add all the numbers together, and all the variables

4n+3(n-2)-64=0

We multiply parentheses

4n+3n-6-64=0

We add all the numbers together, and all the variables

7n-70=0

We move all terms containing n to the left, all other terms to the right

7n=70

n=70/7

n=10

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