-3(6-2y)=4(2y-3)-8

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Solution for -3(6-2y)=4(2y-3)-8 equation: 



-3(6-2y)=4(2y-3)-8

We move all terms to the left:

-3(6-2y)-(4(2y-3)-8)=0

We add all the numbers together, and all the variables

-3(-2y+6)-(4(2y-3)-8)=0

We multiply parentheses

6y-(4(2y-3)-8)-18=0



We calculate terms in parentheses: -(4(2y-3)-8), so:

4(2y-3)-8

We multiply parentheses

8y-12-8

We add all the numbers together, and all the variables

8y-20

Back to the equation:

-(8y-20)



We get rid of parentheses

6y-8y+20-18=0

We add all the numbers together, and all the variables

-2y+2=0

We move all terms containing y to the left, all other terms to the right

-2y=-2

y=-2/-2

y=1

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