(2y/9)=(8/4y)

Solution for (2y/9)=(8/4y) equation:

(2y/9)=(8/4y)

We move all terms to the left:

(2y/9)-((8/4y))=0


Domain of the equation: 4y))!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+2y/9)-((+8/4y))=0

We get rid of parentheses

2y/9-((+8/4y))=0

We calculate fractions


8y^2/36y+()/36y=0

We multiply all the terms by the denominator


8y^2+()=0

We add all the numbers together, and all the variables

8y^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{16}=0$