-3(4y-10)-y=-3(y-2)

Solution for -3(4y-10)-y=-3(y-2) equation:

-3(4y-10)-y=-3(y-2)

We move all terms to the left:

-3(4y-10)-y-(-3(y-2))=0

We add all the numbers together, and all the variables

-1y-3(4y-10)-(-3(y-2))=0

We multiply parentheses

-1y-12y-(-3(y-2))+30=0


We calculate terms in parentheses: -(-3(y-2)), so:

-3(y-2)

We multiply parentheses

-3y+6

Back to the equation:

-(-3y+6)


We add all the numbers together, and all the variables

-13y-(-3y+6)+30=0

We get rid of parentheses

-13y+3y-6+30=0

We add all the numbers together, and all the variables

-10y+24=0

We move all terms containing y to the left, all other terms to the right

-10y=-24

y=-24/-10

y=2+2/5