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-3(4x+9)2(3x+8)=x-(9x-5)
We move all terms to the left:
-3(4x+9)2(3x+8)-(x-(9x-5))=0
We calculate terms in parentheses: -(x-(9x-5)), so:We get rid of parentheses
x-(9x-5)
We get rid of parentheses
x-9x+5
We add all the numbers together, and all the variables
-8x+5
Back to the equation:
-(-8x+5)
-3(4x+9)2(3x+8)+8x-5=0
We add all the numbers together, and all the variables
8x-3(4x+9)2(3x+8)-5=0
We move all terms containing x to the left, all other terms to the right
8x-3(4x+9)2(3x+8)=5
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