-3(4x+3)+4(6x+1)=2(x-1)

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Solution for -3(4x+3)+4(6x+1)=2(x-1) equation: 



-3(4x+3)+4(6x+1)=2(x-1)

We move all terms to the left:

-3(4x+3)+4(6x+1)-(2(x-1))=0

We multiply parentheses

-12x+24x-(2(x-1))-9+4=0



We calculate terms in parentheses: -(2(x-1)), so:

2(x-1)

We multiply parentheses

2x-2

Back to the equation:

-(2x-2)



We add all the numbers together, and all the variables

12x-(2x-2)-5=0

We get rid of parentheses

12x-2x+2-5=0

We add all the numbers together, and all the variables

10x-3=0

We move all terms containing x to the left, all other terms to the right

10x=3

x=3/10

x=3/10

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