3(z-1)=12

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Solution for 3(z-1)=12 equation: 



3(z-1)=12

We move all terms to the left:

3(z-1)-(12)=0

We multiply parentheses

3z-3-12=0

We add all the numbers together, and all the variables

3z-15=0

We move all terms containing z to the left, all other terms to the right

3z=15

z=15/3

z=5

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