-3(4x+3)+4(6x+1)=-2(x-8)+27+2x

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Solution for -3(4x+3)+4(6x+1)=-2(x-8)+27+2x equation: 



-3(4x+3)+4(6x+1)=-2(x-8)+27+2x

We move all terms to the left:

-3(4x+3)+4(6x+1)-(-2(x-8)+27+2x)=0

We multiply parentheses

-12x+24x-(-2(x-8)+27+2x)-9+4=0



We calculate terms in parentheses: -(-2(x-8)+27+2x), so:

-2(x-8)+27+2x

determiningTheFunctionDomain
-2(x-8)+2x+27

We add all the numbers together, and all the variables

2x-2(x-8)+27

We multiply parentheses

2x-2x+16+27

We add all the numbers together, and all the variables

43

Back to the equation:

-(43)



We add all the numbers together, and all the variables

12x-48=0

We move all terms containing x to the left, all other terms to the right

12x=48

x=48/12

x=4

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