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2x(5x-6)=120
We move all terms to the left:
2x(5x-6)-(120)=0
We multiply parentheses
10x^2-12x-120=0
a = 10; b = -12; c = -120;
Δ = b2-4ac
Δ = -122-4·10·(-120)
Δ = 4944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4944}=\sqrt{16*309}=\sqrt{16}*\sqrt{309}=4\sqrt{309}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{309}}{2*10}=\frac{12-4\sqrt{309}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{309}}{2*10}=\frac{12+4\sqrt{309}}{20} $
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