-3(4/5x-4)=4(1/3x+3)

Solution for -3(4/5x-4)=4(1/3x+3) equation:

-3(4/5x-4)=4(1/3x+3)

We move all terms to the left:

-3(4/5x-4)-(4(1/3x+3))=0


Domain of the equation: 5x-4)!=0

x∈R



Domain of the equation: 3x+3))!=0

x∈R


We multiply parentheses

-12x-(4(1/3x+3))+12=0

We multiply all the terms by the denominator


-12x*3x+12*3x+3))-(4(1+3))=0

We add all the numbers together, and all the variables

-12x*3x+12*3x+3))-(44)=0

We add all the numbers together, and all the variables

-12x*3x+12*3x=0

Wy multiply elements

-36x^2+36x=0

a = -36; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·(-36)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*-36}=\frac{-72}{-72}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*-36}=\frac{0}{-72}
=0
$