-3(3y-5)-y=-2(y-3)

Solution for -3(3y-5)-y=-2(y-3) equation:

-3(3y-5)-y=-2(y-3)

We move all terms to the left:

-3(3y-5)-y-(-2(y-3))=0

We add all the numbers together, and all the variables

-1y-3(3y-5)-(-2(y-3))=0

We multiply parentheses

-1y-9y-(-2(y-3))+15=0


We calculate terms in parentheses: -(-2(y-3)), so:

-2(y-3)

We multiply parentheses

-2y+6

Back to the equation:

-(-2y+6)


We add all the numbers together, and all the variables

-10y-(-2y+6)+15=0

We get rid of parentheses

-10y+2y-6+15=0

We add all the numbers together, and all the variables

-8y+9=0

We move all terms containing y to the left, all other terms to the right

-8y=-9

y=-9/-8

y=1+1/8