(4x+1)(3x+8)=0

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Solution for (4x+1)(3x+8)=0 equation:



(4x+1)(3x+8)=0
We multiply parentheses ..
(+12x^2+32x+3x+8)=0
We get rid of parentheses
12x^2+32x+3x+8=0
We add all the numbers together, and all the variables
12x^2+35x+8=0
a = 12; b = 35; c = +8;
Δ = b2-4ac
Δ = 352-4·12·8
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-29}{2*12}=\frac{-64}{24} =-2+2/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+29}{2*12}=\frac{-6}{24} =-1/4 $

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