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52=4x(2x+7)
We move all terms to the left:
52-(4x(2x+7))=0
We calculate terms in parentheses: -(4x(2x+7)), so:We get rid of parentheses
4x(2x+7)
We multiply parentheses
8x^2+28x
Back to the equation:
-(8x^2+28x)
-8x^2-28x+52=0
a = -8; b = -28; c = +52;
Δ = b2-4ac
Δ = -282-4·(-8)·52
Δ = 2448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2448}=\sqrt{144*17}=\sqrt{144}*\sqrt{17}=12\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-12\sqrt{17}}{2*-8}=\frac{28-12\sqrt{17}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+12\sqrt{17}}{2*-8}=\frac{28+12\sqrt{17}}{-16} $
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