-3(3y+3)-11=-6(y+5)+3y

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Solution for -3(3y+3)-11=-6(y+5)+3y equation: 



-3(3y+3)-11=-6(y+5)+3y

We move all terms to the left:

-3(3y+3)-11-(-6(y+5)+3y)=0

We multiply parentheses

-9y-(-6(y+5)+3y)-9-11=0



We calculate terms in parentheses: -(-6(y+5)+3y), so:

-6(y+5)+3y

We add all the numbers together, and all the variables

3y-6(y+5)

We multiply parentheses

3y-6y-30

We add all the numbers together, and all the variables

-3y-30

Back to the equation:

-(-3y-30)



We add all the numbers together, and all the variables

-9y-(-3y-30)-20=0

We get rid of parentheses

-9y+3y+30-20=0

We add all the numbers together, and all the variables

-6y+10=0

We move all terms containing y to the left, all other terms to the right

-6y=-10

y=-10/-6

y=1+2/3

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