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x(x+3)=89
We move all terms to the left:
x(x+3)-(89)=0
We multiply parentheses
x^2+3x-89=0
a = 1; b = 3; c = -89;
Δ = b2-4ac
Δ = 32-4·1·(-89)
Δ = 365
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{365}}{2*1}=\frac{-3-\sqrt{365}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{365}}{2*1}=\frac{-3+\sqrt{365}}{2} $
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