-3(3x-2)=-12x-6+x

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Solution for -3(3x-2)=-12x-6+x equation: 



-3(3x-2)=-12x-6+x

We move all terms to the left:

-3(3x-2)-(-12x-6+x)=0

We add all the numbers together, and all the variables

-3(3x-2)-(-11x-6)=0

We multiply parentheses

-9x-(-11x-6)+6=0

We get rid of parentheses

-9x+11x+6+6=0

We add all the numbers together, and all the variables

2x+12=0

We move all terms containing x to the left, all other terms to the right

2x=-12

x=-12/2

x=-6

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