If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(5x+3)(2x-1)=
We move all terms to the left:
(5x+3)(2x-1)-()=0
We add all the numbers together, and all the variables
(5x+3)(2x-1)=0
We multiply parentheses ..
(+10x^2-5x+6x-3)=0
We get rid of parentheses
10x^2-5x+6x-3=0
We add all the numbers together, and all the variables
10x^2+x-3=0
a = 10; b = 1; c = -3;
Δ = b2-4ac
Δ = 12-4·10·(-3)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-11}{2*10}=\frac{-12}{20} =-3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+11}{2*10}=\frac{10}{20} =1/2 $
| x=0.6x+384x | | (2x+24)=0 | | -4(2x+5)+6=42 | | 2-((1/x)x2)+x=5 | | 2(4x-1)-2(2x+3)=7 | | 3x÷10=9/5 | | (2x+24)(3x-8)=0 | | -4(x)=x+5 | | 11=-2x-16 | | 100=0.35x+70 | | y2−14y=−50 | | 10n-8n=5+n | | 22=-5x+2(x-4) | | m+4=-1-12 | | (4x+5)(-x-9)=0 | | 6*(x-8)=-12 | | 4n-12+2n=2 | | 25=-10r-9-6 | | p-(14.50)=53 | | (2x-8)(2x+8)=0 | | 4*(x+10)=16 | | 4*(x-2)=-40 | | 12−2f=4 | | 4*(x-12)=-28 | | 3*(x+9)=24 | | 5x^2-9x=2x^2-2x | | 5x−1=2(x+4)5x−1=2x+87x−1=8 7x=7 x=1 | | 12−2s=8 | | 3*(x+9)=30 | | q3− 2=1 | | 14=2p-9p | | 16x^2+128x-120=0 |