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-3(2y-5)+5y=5(y+5)
We move all terms to the left:
-3(2y-5)+5y-(5(y+5))=0
We add all the numbers together, and all the variables
5y-3(2y-5)-(5(y+5))=0
We multiply parentheses
5y-6y-(5(y+5))+15=0
We calculate terms in parentheses: -(5(y+5)), so:We add all the numbers together, and all the variables
5(y+5)
We multiply parentheses
5y+25
Back to the equation:
-(5y+25)
-1y-(5y+25)+15=0
We get rid of parentheses
-1y-5y-25+15=0
We add all the numbers together, and all the variables
-6y-10=0
We move all terms containing y to the left, all other terms to the right
-6y=10
y=10/-6
y=-1+2/3
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