1=1/3(-1)+b

Solution for 1=1/3(-1)+b equation:

1=1/3(-1)+b

We move all terms to the left:

1-(1/3(-1)+b)=0


Domain of the equation: 3(-1)+b)!=0

b∈R


We multiply all the terms by the denominator


-(1+1*3(-1)+b)=0


We calculate terms in parentheses: -(1+1*3(-1)+b), so:

1+1*3(-1)+b

determiningTheFunctionDomain
b+1+1*3(-1)

We add all the numbers together, and all the variables

b-2

Back to the equation:

-(b-2)


We get rid of parentheses

-b+2=0

We add all the numbers together, and all the variables

-1b+2=0

We move all terms containing b to the left, all other terms to the right

-b=-2

b=-2/-1

b=+2