-3(2y-4)=7(1-y)

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Solution for -3(2y-4)=7(1-y) equation: 



-3(2y-4)=7(1-y)

We move all terms to the left:

-3(2y-4)-(7(1-y))=0

We add all the numbers together, and all the variables

-3(2y-4)-(7(-1y+1))=0

We multiply parentheses

-6y-(7(-1y+1))+12=0



We calculate terms in parentheses: -(7(-1y+1)), so:

7(-1y+1)

We multiply parentheses

-7y+7

Back to the equation:

-(-7y+7)



We get rid of parentheses

-6y+7y-7+12=0

We add all the numbers together, and all the variables

y+5=0

We move all terms containing y to the left, all other terms to the right

y=-5

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