-3(2x-5/6)=(-5/4x+3)=0,5

Solution for -3(2x-5/6)=(-5/4x+3)=0,5 equation:

-3(2x-5/6)=(-5/4x+3)=0.5

We move all terms to the left:

-3(2x-5/6)-((-5/4x+3))=0


Domain of the equation: 4x+3))!=0

x∈R


We add all the numbers together, and all the variables

-3(+2x-5/6)-((-5/4x+3))=0

We multiply parentheses

-6x-((-5/4x+3))+5/6*3=0

We calculate fractions


-6x+()/4x+20x/4x=0

We multiply all the terms by the denominator


-6x*4x+20x+()=0

We add all the numbers together, and all the variables

20x-6x*4x=0

Wy multiply elements

-24x^2+20x=0

a = -24; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·(-24)·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*-24}=\frac{-40}{-48}
=5/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*-24}=\frac{0}{-48}
=0
$