-2(y+6)=2y-6+4(3y+2)

Solution for -2(y+6)=2y-6+4(3y+2) equation:

-2(y+6)=2y-6+4(3y+2)

We move all terms to the left:

-2(y+6)-(2y-6+4(3y+2))=0

We multiply parentheses

-2y-(2y-6+4(3y+2))-12=0


We calculate terms in parentheses: -(2y-6+4(3y+2)), so:

2y-6+4(3y+2)

determiningTheFunctionDomain
2y+4(3y+2)-6

We multiply parentheses

2y+12y+8-6

We add all the numbers together, and all the variables

14y+2

Back to the equation:

-(14y+2)


We get rid of parentheses

-2y-14y-2-12=0

We add all the numbers together, and all the variables

-16y-14=0

We move all terms containing y to the left, all other terms to the right

-16y=14

y=14/-16

y=-7/8