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-3(2x-5)+7x-14+x-4+2(10+2x)=18-11x+4(2-x+4x)-0.5x+1/2x-19
We move all terms to the left:
-3(2x-5)+7x-14+x-4+2(10+2x)-(18-11x+4(2-x+4x)-0.5x+1/2x-19)=0
Domain of the equation: 2x-19)!=0We add all the numbers together, and all the variables
x∈R
-3(2x-5)+7x+x+2(2x+10)-(18-11x+4(3x+2)-0.5x+1/2x-19)-14-4=0
We add all the numbers together, and all the variables
8x-3(2x-5)+2(2x+10)-(18-11x+4(3x+2)-0.5x+1/2x-19)-18=0
We multiply parentheses
8x-6x+4x-(18-11x+4(3x+2)-0.5x+1/2x-19)+15+20-18=0
We multiply all the terms by the denominator
8x*2x-19)-6x*2x-19)+4x*2x-19)-(18-11x+4(3x+2)-0.5x+1+15*2x-19)+20*2x-19)-18*2x-19)=0
Wy multiply elements
16x^2-19)-6x*2x-19)+4x*2x-19)-(18-11x+4(3x+2)-0.5x+1+15*2x-19)+20*2x-19)-18*2x-19)=0
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