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x=3/4x+9
We move all terms to the left:
x-(3/4x+9)=0
Domain of the equation: 4x+9)!=0We get rid of parentheses
x∈R
x-3/4x-9=0
We multiply all the terms by the denominator
x*4x-9*4x-3=0
Wy multiply elements
4x^2-36x-3=0
a = 4; b = -36; c = -3;
Δ = b2-4ac
Δ = -362-4·4·(-3)
Δ = 1344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1344}=\sqrt{64*21}=\sqrt{64}*\sqrt{21}=8\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-8\sqrt{21}}{2*4}=\frac{36-8\sqrt{21}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+8\sqrt{21}}{2*4}=\frac{36+8\sqrt{21}}{8} $
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