-3(2v-3)+2v=3+2(5v-2)

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Solution for -3(2v-3)+2v=3+2(5v-2) equation: 



-3(2v-3)+2v=3+2(5v-2)

We move all terms to the left:

-3(2v-3)+2v-(3+2(5v-2))=0

We add all the numbers together, and all the variables

2v-3(2v-3)-(3+2(5v-2))=0

We multiply parentheses

2v-6v-(3+2(5v-2))+9=0



We calculate terms in parentheses: -(3+2(5v-2)), so:

3+2(5v-2)

determiningTheFunctionDomain
2(5v-2)+3

We multiply parentheses

10v-4+3

We add all the numbers together, and all the variables

10v-1

Back to the equation:

-(10v-1)



We add all the numbers together, and all the variables

-4v-(10v-1)+9=0

We get rid of parentheses

-4v-10v+1+9=0

We add all the numbers together, and all the variables

-14v+10=0

We move all terms containing v to the left, all other terms to the right

-14v=-10

v=-10/-14

v=5/7

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