2v-1+2(4v+2)=-4(v+1)

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Solution for 2v-1+2(4v+2)=-4(v+1) equation: 



2v-1+2(4v+2)=-4(v+1)

We move all terms to the left:

2v-1+2(4v+2)-(-4(v+1))=0

We multiply parentheses

2v+8v-(-4(v+1))+4-1=0



We calculate terms in parentheses: -(-4(v+1)), so:

-4(v+1)

We multiply parentheses

-4v-4

Back to the equation:

-(-4v-4)



We add all the numbers together, and all the variables

10v-(-4v-4)+3=0

We get rid of parentheses

10v+4v+4+3=0

We add all the numbers together, and all the variables

14v+7=0

We move all terms containing v to the left, all other terms to the right

14v=-7

v=-7/14

v=-1/2

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